Thursday, November 7, 2019

mind and machine essays

mind and machine essays Technology has traditionally evolved as the result of human needs. Invention, when prized and rewarded, will invariably rise-up to meet the free market demands of society. It is in this realm that Artificial Intelligence research and the resultant expert systems have been forged. Much of the material that relates to the field of Artificial Intelligence deals with human psychology and the nature of consciousness. Exhaustive debate on consciousness and the possibilities of consciousnessness in machines has adequately, in my opinion, revealed that it is most unlikely that we will ever converse or interract with a machine of artificial consciousness. In John Searle's collection of lectures, Minds, Brains and Science, arguments centering around the mind-body problem alone is sufficient to convince a reasonable person that there is no way science will ever unravel the mysteries of consciousness. Key to Searle's analysis of consciousness in the context of Artificial Intelligence machines are refutations of strong and weak AI theses. Strong AI Theorists (SATs) believe that in the future, mankind will forge machines that will think as well as, if not better than humans. To them, pesent technology constrains this achievement. The Weak AI Theorists (WATs), almost converse to the SATs, believe that if a machine performs functions that resemble a human's, then there must be a correlation between it and consciousness. To them, there is no technological impediment to thinking machines, because our most advanced machines already think. It is important to review Searle's refutations of these respective theorists' proposition to establish a foundation (for the purpose of this essay) for discussing the applications of Artificial Intelligence, both now and in the future. Strong AI Thesis, according to Searle, can be described in four basic propositions. Proposition one categorizes human thought as the result of computational processes. G...

Monday, November 4, 2019

The Sociological Perspectives Essay Example | Topics and Well Written Essays - 500 words

The Sociological Perspectives - Essay Example The functionalist perspective views the world as a set of groups that coexist based on mutual need and cooperation. It is through this means that society is able to reach and maintain equilibrium. Durkheim, Comte, and Spencer pioneered this sociological perspective, but Robert Merton elaborated on the theory. He viewed societal consequences as being manifest, latent, and latent dysfunctional. Manifest functions are the positive and intended outcome of a group on society. Latent functions are the unintended consequences that help society maintain order. The latent dysfunctions are unintended negative results that continually upset and shape society. Our family was lower middle class and as such we filled the role of working in the factories and the mills. In return society provided us with adequate income and substantial opportunities. In doing so, our social class fulfilled its function and was rewarded by other groups in society through peaceful coexistence Karl Marx, the most well known conflict theorist, viewed the world as groups that were competing for the available resources. He generally defined conflict in terms of wealth and saw it as two classes; the bourgeoisie (capitalists) and the proletariat (workers).

Saturday, November 2, 2019

Compare Term Paper Example | Topics and Well Written Essays - 750 words

Compare - Term Paper Example Thus, it is paramount to understand the motives for these explorers to set out on the journeys to the Americans Most of the Spanish explorers were sent by the Spanish monarchs of the time. Christopher Columbus, Hernando Cortes, and Vasco Nunez are among the Spanish explorers that affected the world. Isabella was the queen of Castile. She sent Columbus to explore the world for the benefit of the religion and Castile. In September 1492, Columbus sailed with three ships, a crew of less than ninety men and a lack of fundamental understanding of the size of the earth. After about one month, on October 12, 1492, Christopher Columbus voyage cited an isolated chain of Island, which came to be the Bahamas. On the second voyage, Columbus landed on St. Croix where he was welcomed with hostility from the locals. Vasco Nunez was the other notable Spanish explorer. While on an expedition, Nunez cited the Pacific Ocean in 1513 while searching for gold. Nunez claimed the area around the Pacific Ocean and opened the way for further Spanish exploration and conquest. Christopher Columbus voyage set out in 1492 to explore the world through the Atlantic Ocean. The same year was also important to the Spanish for others different from discovery. The Spanish monarchs issued an order for everyone to convert to Christianity or leave Spain. In the urge to continue their expansion and spread of Christianity, the queen sent Christopher Columbus on a mission to spread information about God and to benefit Spain in terms of trade to Asia. They found the Bahamas, Hispaniola and Cuba. Columbus voyage first landing and mainland explorations were in the Caribbean regions and South America (Reilly 332). Vasco Nunez explored the Gulf of Uraba near the present day Colombia and Hispaniola. Christopher Columbus and his men were not successful in their mission. Instead of reaching Asia as stated by their mission, they landed in the Caribbean. Columbus

Thursday, October 31, 2019

Marketing management Research Paper Example | Topics and Well Written Essays - 750 words

Marketing management - Research Paper Example 2. A company that has a well-executed branding strategy will enjoy the good aspect of marketing. This is because customers will be able to identify themselves with the good due to its color, brand name and even the price. Consumers will enjoy the benefits of easy selection and budgeting of their selected brand. With regard to a newly launched product, the brand name provides the advantage especially due to the customer base already created by pioneer brands. 3. Most of the new products fail in the market because of several reasons. One of the reasons is the level of competition. Most of the newly launched products are unable to compete effectively in the market hence fail. Most of the marketers also fail in conducting feasibility tests before launching their products in the market. In addition to this, poor branding strategies and failure to connect the new product with pioneer brand creates a loophole which eventually leads to the failure. Marketers are therefore under obligation to conduct a proper feasibility test before they introduce a new product. They must ensure that the product is appealing to the customers and meeting their demands in terms of price quality and quantity. 4. Most marketers are have engaged in understanding the psychological behavior of the consumers and are now utilizing the strategy of perceived value. This means that the value of the price of the goods or services are according to what the customers thinks they are. The key to perceived value pricing is providing the customer with what they want in form of size, quality, quantity, and price. Once this is done customer loyalty follows and this is the most important aspect of perceived pricing. The marketer is able to predict the price to be paid through customer loyalty, customer demands and customer cares services. 5. One of the strategies is to increase the compensation such that the highest marketer gets the highest commission. This will act

Tuesday, October 29, 2019

Euro Behaviour Essay Example | Topics and Well Written Essays - 2000 words

Euro Behaviour - Essay Example From the report it is clear that  economic performance of a trade block depend more on individual countries performance. In our analysis, we intend to evaluate euro’s performance and as such will rely more on the overall activity within member countries. Euro is not political affiliated and thus depend in multi-nation policies regarding the member countries economic performance. When crisis in economic activity within one trade block occur, the effects easily spill to the global economic and asset market. The European Union, as a trade block, has frequently suffered such.According to the report findings  the links in international financial and asset markets are key determinants of a currency’s exchange rate. Single currency or states supremacy cannot influence the rates that her currencies are accorded. Macroeconomics teaches that multiple factors are put into play in regard to determining a currency’s worth in the international market. Individual states cur rency is rated on a scale that is unanimously accepted within the trading scope against a common denomination; majorly the U.S dollar, yen or the euro. However, the rates are never constant varying on the prevailing economic performances as determined by the World Bank. ‘Purchasing power parity’ (PPP) compares rates of trade and prices within a state. Projections of future interest rates of a currency relative to nominal interests are determined by the interest rate parity. (Cumby and Obstfeld, 1982, 1-2). Therefore, at the macro and micro level performance of an economy, the policies made always have an impact to the valuation of her currency. However, the determination of these indices within an economic block like the EU is not dependent on a single country but rather on sum of the overall economic performance of the economic block. The Euro use has expanded very much within the EU region and is now estimated to be in used throughout

Sunday, October 27, 2019

Maths Teaching Guide: Algebraic Expressions

Maths Teaching Guide: Algebraic Expressions 6 Algebraic Expressions You know to write the terms, coefficients and factors of an algebraic expression. to classify an algebraic expression as monomial, binomial, trinomial. to identify like terms. to add and subtract algebraic expression. You will learn multiplication and division of given polynomials. the difference between an identity and an equation. algebraic identities and their applications. factorization of algebraic expression by regrouping , by taking common factors or using algebraic identities. Let us recall the basic definitions of algebra Constants and variables : A quantity having a fixed numerical value is called a constant whereas variables in algebra are letters such as x, y, z or any other letter that can be used to represent unknown numbers. Algebraic expression : An expression which has a combination of constants and variables connected to each other by one or more operation (+,-,X,à ·) is called an algebraic expression. Example are all algebraic expressions Term : The parts of an algebraic expression separated by an addition or a subtraction sign are called terms of the expression. In the expression the terms of the expression are are variable terms as their values will change with the value of x, while (-4) is a constant term. On the basis of the number of terms in an algebraic expression, they are classified as monomials, binomials, trinomials and polynomials. Monomials are algebraic expressions having one term . Binomials are algebraic expressions having two terms. Trinomials are algebraic expressions having three terms. Polynomials are algebraic expressions having one or more than one term. Remember – Only expressions with positive powers of variables are called polynomials. An expression of the type is not a polynomial as and the power of variable p is (- 1) which is not a whole number. Example 1 Classify the algebraic expressions as monomials, binomials or trinomials. Solution binomial monomial trinomial monomial binomial Like and Unlike terms : Terms having the same algebraic factors are called like terms . The numerical coefficients may be different. 2x2yz, 5x2yz, 8x2yz and 2x2yz are like terms 3p 3q2, 7p 3q2and 9p 3q2 are also like terms. Unlike terms : Terms having different algebraic factors are called unlike terms, , 3x2yz 3p 3q2 are unlike terms. Addition and Subtraction of Algebraic Expressions. In algebra, like terms can be added or subtracted. To add or subtract algebraic expressions we can use the horizontal method or the column method. The horizontal method All algebraic expressions are written in a horizontal line; the like terms are then grouped. The sum or difference of the numerical coefficients is then found. Example 2 Add the following Solution Example 3 Subtract Solution The column method In the column method, each expression is written in a separate row in such a way that like terms are arranged one below the other in a column. The sum or difference of the numerical coefficients is then found. Example 4 Add : Solution To add by horizontal method, collect the like terms and add coefficients. To add by column method, arrange the like terms in column and add Example 5 Subtract : Solution We know that the subtraction of two algebraic expressions or terms is addition of the additive inverse of the second term to the first term. Since the additive inverse of a term has opposite sign of the term, hence we can say that in subtraction of algebraic expressions change + to – and change – to + for the term to be subtracted and then add the two terms To subtract by column method, arrange the like terms in columns and change the sign of the subtrahend Example 6 What should be added to to get Solution The expression to be added will be Exercise 6.1 Classify the algebraic expressions as monomials, binomials or trinomials. Also write the terms of the expression Add the following algebraic expressions by the horizontal method Add the following algebraic expressions. Subtract the following expressions. Subtract the sum of from the sum of . Two adjacent sides of a rectangle are . What will be the perimeter of the rectangle. The perimeter of a triangle is and the measure of two sides is. What will be the measure of the third side? What should be added to to get . What should be subtracted from to get By how much is greater than . Multiplication of Algebraic Expressions Multiplication of a monomial by another monomial To multiply 2 monomials Multiply the numerical coefficients Multiply the literal coefficients and use laws of exponents if variables are same. The product of two monomials is always a monomial. Example 1 Find the product of Solution Geometrical interpretation of product of two monomials The area of a rectangle is given by the product of length and breadth. If we consider the length as l and breadth as b, then Area of rectangle = l x b Thus, it can be said that the area of a rectangle is product of two monomials. Let us consider a rectangle of length 4p and breadth 3p, Area of rectangle ABCD =AB x AD = 4p x 3p = 12p2 Multiplication of a monomial by a binomial To multiply a monomial by a binomial, we use the distributive law Multiply the monomial by the first term Multiply the monomial by the second term of the binomial. The result is the sum of the two terms The product of a monomial and a binomial is always a binomial. Example 2 Find the product Solution Example 3 Multiply Solution Geometrical interpretation of product of a monomial and a binomial Area of rectangle = l x b Let us draw a rectangle ABCD with length (p+q) and breadth k. Take a point P on AB such that AP = p and PB = q. Draw a line parallel to AD from the point P, PQà ¢Ã‚ «Ã‚ ½AD meeting DC at Q. Area of rectangle ABCD = area of rectangle APQD +area of rectangle PBCQ = k x p + k x q = k(p + q) Thus, the product k(p + q) represents the area of a rectangle with length as a binomial (p+q) and breadth as a monomial k. Multiplication of a monomial by a polynomial To multiply a monomial with a binomial, we can extend the distributive law further The product of a monomial and a polynomial is a polynomial. Example 3 Find the product of Solution We have multiplied horizontally in all the above examples We can also multiply vertically as shown below Multiply Geometrical interpretation of product of a monomial and a polynomial Let us consider a rectangle with length = (p +q + r) and breadth= k Take points M and N on AB such that AM = p and MN = q and NB = r .from the points M and N draw parallel to AD, MXà ¢Ã‚ «Ã‚ ½AD and NYà ¢Ã‚ «Ã‚ ½AD meeting DC at X and Y. Area of rectangle ABCD = area of rectangle AMXD +area of rectangle MNYX +area of rectangle NBCY Area of rectangle ABCD=pk + qk + rk = k(p + q+ r) Thus, the product of a monomial and a polynomial represents the area of a reactangle with length as a polynomial and breadth as a monomial. Example 4 Simplify Solution Multiplication of binomials To multiply two binomials (a + b) and (c + d) we will again use the distributive law of multiplication over addition twice Example 5 Multiply Solution We have multiplied horizontally in all the above examples We can also multiply vertically as shown below Multiplication of polynomial by a polynomial A polynomial is an algebraic expression having 1 or more than one term To multiply two polynomials, we will use the distributive property that is multiply each term of the first polynomial with each term of the second polynomial. Example 6 Multiply Solution We have multiplied horizontally in the above example, We can also multiply vertically as shown below Exercise 6.2 Multiply the following monomials 2a and 9b Find the following products and evaluate for x = 1, y = -1 Find the following products by horizontal method Find the following products using column method Find the area of the rectangle with the given measurements Length = 3p, breadth = 4p Length = (2a+4), breadth = 5a Multiply the following Simplify the following expressions Multiply . Simplify If the length of a rectangle is and breadth is 3abc,find the area of the rectangle. Algebraic identities An identity is a special type of equation in which the LHS and the RHS are equal for all values of the variables. The above equation is true for all possible values of a and b; so it is called an identity. An identity is different from equation as an equation is not true for all values of variables,;it has a unique solution. Example There are a number of identities which are used in mathematics to make calculations easy. We are going to study 4 basic identities Verification of identities in this identity a and b can be positive or negative Geometrical verification of identities Geometrical demonstration for. Draw a square with length as shown in the figure. Let the area of original square be X then, area of Square PQRS=(side)2 ∠´ , Mark a point M on PQ such that length of PM = a and length of MQ= b. Draw a line MC parallel to PS intersecting SR at C. Similarly, mark a point B on RQ such that RB = a and QB = b. Draw a line BD parallel to QP intersecting PS at D. The whole square is divided into 2 squares and 2 rectangles say A1, A4,A2and A3 Area of Square X1 = side2= a2 Area of rectangle X2= length x breadth = ab Area of rectangle X3= length x breadth = ab Area of Square X4 = side2= b2 area of Square PQRS = sum of inside area = area of X1+ area of X2+ area ofX3+ area ofX4 Geometrically demonstration for . We draw a square with length a as shown in the figure. Let the area of original square is A Then, area of Square PQRS=(side)2 ∠´ Mark a point M on PQ such that the length of PM = a-b and length of MQ= b. Draw a line MC parallel to PS intersecting SR at C. Similarly, mark a point B on RQ such that RB = a b and QB = b. Draw a line BD parallel to QP intersecting PS at D. The whole square

Friday, October 25, 2019

Just Another Day at the Office :: English Literature Essays

Just Another Day at the Office Personal computer (pc) repair technicians and doctors have a lot in common. Patients arrive at the doctor’s door bearing all manner of complaints or problems. I am sure doctors have seen and heard about every type of ignorant stunt a person can think of or do. My name is Skeeter Jones, and I have been a pc repair technician for approximately fifteen years. Like a doctor, I thought I had seen and heard of every crazy stunt imaginable until I received a call from Headaches, Incorporated about a computer crash. When I arrived at the job site, Lola and Chase, the office and terminal managers, greeted me. â€Å"Boy! Are we ever glad to see you,† they both cried in unison, â€Å"We have completely screwed up the computer.† â€Å"Well, show me the computer that is down while you tell me what happened,† I replied. â€Å"Linda, Lola’s co-worker, told us upgrading our computer system from Windows 95 to 98 would be easy for us to do ourselves. All we had to do was purchase the Windows 98 upgrade compact disc (CD),† Chase said. â€Å"Except, we could not find the CD.† Lola chimed in, â€Å"We picked out this CD instead. The salesman at Office Depot said, ’It would work just as well to upgrade our system.’† I looked down at the box she was holding in her hands. The words â€Å"Windows 2000 Upgrade† stared back at me in big, white letters. I just stood there for a minute shaking my head, and I silently groaned to myself. â€Å"Oh God! How could anybody be that stupid,† I thought. With an audible sigh, I said aloud, â€Å"Let me run a few diagnostic tests. I will be able to tell you how much damage has occurred in a couple of minutes.† I started with the basic stuff like making sure the computer would boot up. Then, I progressed layer by layer to the heart of the system. The tests took me nearly three hours to complete. As I dug deeper and deeper into the computer, I was utterly amazed at how much damage they had wreaked in such a short amount of time and with only an upgrade software kit. â€Å"Well guys, it looks as if you have managed to confuse the hell out of this computer,† I told them, â€Å"You have two different types of file systems on it now.